constant folding failed: Invalid argument: Unsupported type: 21问题

来源:5-8 编写从训练文件获取音符的方法

慕粉6492109

2019-08-16

执行第5章, train.py后提示以下几行代码,

Train on 37425 samples
Epoch 1/100
2019-08-16 18:15:15.183678: E tensorflow/core/grappler/optimizers/meta_optimizer.cc:502] constant folding failed: Invalid argument: Unsupported type: 21
2019-08-16 18:15:15.221236: E tensorflow/core/grappler/optimizers/meta_optimizer.cc:502] constant folding failed: Invalid argument: Unsupported type: 21
2019-08-16 18:15:16.736293: E tensorflow/core/grappler/optimizers/meta_optimizer.cc:502] constant folding failed: Invalid argument: Unsupported type: 21
2019-08-16 18:15:16.773799: E tensorflow/core/grappler/optimizers/meta_optimizer.cc:502] constant folding failed: Invalid argument: Unsupported type: 21

之后继续输出每次训练的loss 值

ex:
10030/37425 【=>…】 -ETA: 15:21 -loss:5.3583
.
.
一直直行到
30630/36425 【=>…】 -ETA: 15:21 -loss:4.3583Killed 结束, 也没有生成 .hdf5 文件

请问这是为什么呢?
以及该如何解决呢?

写回答

1回答

Oscar

2019-09-18

你的Tensorflow版本是多少?

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