final int count = i; 传参到线程任务中的时机是什么?
来源:5-5 线程不安全类与写法-2
![](http://img1.sycdn.imooc.com/user/54584dc4000118d302200220-100-100.jpg)
梨多情
2020-04-09
public static void main(String[] args) throws Exception {
ExecutorService executorService = Executors.newCachedThreadPool();
final Semaphore semaphore = new Semaphore(threadTotal);
final CountDownLatch countDownLatch = new CountDownLatch(clientTotal);
for (int i = 0; i < clientTotal; i++) {
final int count = i;
// int count = i;
executorService.execute(() -> {
try {
semaphore.acquire();
update(count);
semaphore.release();
} catch (Exception e) {
log.error(“exception”, e);
}
countDownLatch.countDown();
});
}
countDownLatch.await();
executorService.shutdown();
log.info(“size:{}”, list.size());
}
问题1:
final int count = i;
将 i 传参到线程任务中的时机是什么?
问题2:
我改用线程安全的类测,有没有 final 似乎没影响啊?
// private static List list = new ArrayList<>();
private static List list = Collections.synchronizedList(new ArrayList());
1回答
-
Jimin
2020-04-09
时机就是execute方法执行时,定义为final是因为传入线程池里的变量不能被修改,从我们自己程序而言他没什么意义,但线程池使用时需要这样做
032020-04-15
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