widgets.add(_item(key, CITY_NAMES[key])); 报错问题.. 求解
来源:10-3 基于ExpansionTile实现可展开的列表【列表还可以这样做】
Dejan_he
2023-01-12
完整的代码如下:
import 'package:flutter/material.dart';
const Map<String, List<String>> CITY_NAMES = {
'北京': ['东城区', '西城区', '朝阳区', '丰台区', '石景山区', '海淀区', '顺义区'],
'上海': ['黄浦区', '徐汇区', '长宁区', '静安区', '普陀区', '闸北区', '虹口区'],
'广州': ['越秀', '海珠', '荔湾', '天河', '白云', '黄埔', '南沙', '番禺'],
'深圳': ['南山', '福田', '罗湖', '盐田', '龙岗', '宝安', '龙华'],
'杭州': ['上城区', '下城区', '江干区', '拱墅区', '西湖区', '滨江区'],
'苏州': ['姑苏区', '吴中区', '相城区', '高新区', '虎丘区', '工业园区', '吴江区']
};
void main() => runApp(MyApp());
class MyApp extends StatefulWidget {
@override
_MyAppState createState() => _MyAppState();
}
class _MyAppState extends State<MyApp> {
String countString = '';
String localCount = '';
@override
Widget build(BuildContext context) {
return MaterialApp(
home: Scaffold(
appBar: AppBar(
title: Text('列表展开与收起'),
),
body: Container(
height: 200,
child: ListView(
scrollDirection: Axis.horizontal,
children: _buildList(),
),
),
),
);
}
List<Widget> _buildList() {
List<Widget> widgets = [];
CITY_NAMES.keys.forEach((key) {
widgets.add(_item(key, CITY_NAMES[key]));
});
return widgets;
}
Widget _item(String city, List<String> subCities) {
return ExpansionTile(
title: Text(
city,
style: TextStyle(color: Colors.black54, fontSize: 20),
),
children: subCities.map((subCity) => _buildSub(subCity)).toList(),
);
}
Widget _buildSub(String subCity) {
return FractionallySizedBox(
widthFactor: 1,
child: Container(
height: 50,
margin: EdgeInsets.only(bottom: 5),
decoration: BoxDecoration(color: Colors.lightBlueAccent),
child: Text(subCity),
));
}
}
报错信息:
Launching lib\main.dart on Android SDK built for x86 in debug mode...
Running Gradle task 'assembleDebug'...
lib/main.dart:44:40: Error: The argument type 'List<String>?' can't be assigned to the parameter type 'List<String>' because 'List<String>?' is nullable and 'List<String>' isn't.
- 'List' is from 'dart:core'.
widgets.add(_item(key, CITY_NAMES[key]));
^
FAILURE: Build failed with an exception.
写回答
1回答
-
对照下这块课程源码检查下你的代码实现看是否有出入的地方
https://coding.m.imooc.com/questiondetail.html?qid=134654042023-01-17
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