4回答

悟空

2020-01-28

已采纳

都是执行wait();，所以都是waiting状态

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3

悟空

回复

qq_慕圣9338304

是对的

2020-01-30

共3条回复

qq_慕圣9338304

提问者

2020-01-27

这是结果图

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qq_慕圣9338304

提问者

2020-01-27

package threadcoreknowledge.sixstates;

/*
    展示blocked，waiting，timed-waiting三种状态
 */

public class blockedwaitingtimedwaiting implements Runnable{
    public static void main(String[] args) {
        blockedwaitingtimedwaiting runnable=new blockedwaitingtimedwaiting();
        Thread thread1=new Thread(runnable);
        thread1.start();
        Thread thread2=new Thread(runnable);
        thread2.start();
        try{
            Thread.sleep(5);
        }catch (InterruptedException e){
            e.printStackTrace();
        }
        //打印出timed-waiting状态，因为正在执行Thread.sleep(1000)
        System.out.println(thread1.getState());
        //打印出blocked状态，因为thread2想拿到syn()的锁却拿不到
        System.out.println(thread2.getState());
        try{
            Thread.sleep(2000);
        }catch (InterruptedException e){
            e.printStackTrace();
        }
        //打印出waiting状态，由于等了2000ms，在下面run方法中进入了wait(),所以确保是在waiting状态
        System.out.println(thread2.getState());
        System.out.println(thread1.getState());
    }

    @Override
    public void run() {
        syn();
    }

    private synchronized void syn(){
        try{
            Thread.sleep(1000);
            wait();
        }catch (InterruptedException e){
            e.printStackTrace();
        }
    }
}

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悟空

2020-01-27

麻烦你把你的代码贴一下哈，我看了代码才能分析

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