貌似不需要p1 p1变量
来源:5-4 LeetCode:2. 两数相加

背着行囊独自流浪
2021-03-27
var addTwoNumbers = function(l1, l2) {
const dummyHead = new ListNode(0);
let p = dummyHead;
let carry = 0;
while (l1 || l2) {
const v1 = l1 ? l1.val : 0;
const v2 = l2 ? l2.val : 0;
const v3 = v1 + v2 + carry;
p.next = new ListNode(v3 % 10);
carry = Math.floor(v3 / 10);
if (l1) {
l1 = l1.next;
}
if (l2) {
l2 = l2.next;
}
p = p.next;
}
if (carry) {
p.next = new ListNode(carry);
}
return dummyHead.next;
};
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1回答
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lewis
2021-03-29
也行吧,在js中,函数参数相当于拷贝
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