网络请求如果需要body参数要怎么传呀？if (request.httpMethod() == HttpMethod.GET) {
response = await dio.get(request.url(), options: options);
} else if (request.httpMethod() == HttpMethod.POST) {
response = await dio.post(request.url(),
data: request.body,
queryParameters: request.params,
options: options);
} else if (request.httpMethod() == HttpMethod.DELETE) {
response = await dio.delete(request.url(),
data: request.params, options: options);
}

我这样写好像有问题，params被添加了两次id和look
http://xx.xx.xx.xx/form/automForm/getFormInfo/form_53aa4461a279a2d8?look=false&id=a925d4530f1246fb8d11bb73b79f22bf&look=false&id=a925d4530f1246fb8d11bb73b79f22bf

我的body在baseRequest
dynamic body;
///添加body
BaseRequest addBody(String bodyStr) {
body = bodyStr;
return this;
}
上面那个请求我的body并没有传值，是否有更合适的办法呀？