为什么获取请求来源的ip要像老师代码里的那么复杂?
来源:2-4 基于SpringBoot初始化项目

洛奇2019
2023-05-28
/** * 获取IP地址 * * @param request * @return */ public static String getIpAddress(HttpServletRequest request) { if (request == null) { return "unknown"; } String ip = request.getHeader("x-forwarded-for"); if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) { ip = request.getHeader("Proxy-Client-IP"); } if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) { ip = request.getHeader("X-Forwarded-For"); } if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) { ip = request.getHeader("WL-Proxy-Client-IP"); } if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) { ip = request.getHeader("X-Real-IP"); } if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) { ip = request.getRemoteAddr(); } return "0:0:0:0:0:0:0:1".equals(ip) ? "127.0.0.1" : ip; }
我们在公司的的项目里都是直接
request.getRemoteAddr();
来获取客户端ip,只是这样是不严谨的吗?会有什么问题吗?
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这样如果是代理地址的话,会获取不到哈
012023-05-28
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