为什么获取请求来源的ip要像老师代码里的那么复杂?
来源:2-4 基于SpringBoot初始化项目
洛奇2019
2023-05-28
/**
* 获取IP地址
*
* @param request
* @return
*/
public static String getIpAddress(HttpServletRequest request) {
if (request == null) {
return "unknown";
}
String ip = request.getHeader("x-forwarded-for");
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("X-Forwarded-For");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("X-Real-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return "0:0:0:0:0:0:0:1".equals(ip) ? "127.0.0.1" : ip;
}我们在公司的的项目里都是直接
request.getRemoteAddr();
来获取客户端ip,只是这样是不严谨的吗?会有什么问题吗?
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1回答
-
这样如果是代理地址的话,会获取不到哈
012023-05-28
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