Observable方法问题
来源:5-6 响应式编程

慕粉4270219
2018-12-03
from这个方法没有了吗?
是因为版本不一样吗
怎么解决
写回答
3回答
-
const source = from([1, 2, 3, 4]);
const example = source.pipe(filter(e => e % 2 === 0));
const multiple = example.pipe(map(e => e * e));
const subscribe = multiple.subscribe(
e => console.log(e),
error => console.log(error),
() => console.log('结束啦!')rxjs版本问题吧,https://rxjs-cn.github.io/learn-rxjs-operators/
222019-03-02 -
背着行囊独自流浪
2019-02-16
import { from } from 'rxjs'; import { filter, map } from 'rxjs/operators'; from([1, 2, 3, 4]) .pipe( filter(e => e % 2 === 0), map(e => e * e) ) .subscribe( e => console.log(e), err => console.error(err), () => console.log('结束啦!') );
00 -
JoJo
2018-12-13
import 'rxjs/Rx'
00
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