package main

import (
	"fmt"
	"time"
)

type test struct {
	taskChan chan int
	quitChan chan struct{}
}

func main() {
	t := test{}
	t.taskChan = make(chan int)
	t.quitChan = make(chan struct{})

	//
	go func() {
		t.taskChan <- 1
		fmt.Println("pushed task")
	}()
	go func() {
		// close(t.quitChan)
		t.quitChan <- struct{}{}
		fmt.Println("closed quit chan")
	}()
	go t.consume()
	time.Sleep(time.Millisecond * 10)
}

func (t *test) consume() {
	for {
		select {
		case task := <-t.taskChan:
			fmt.Println("received task:", task)
			return
		case <-t.quitChan:
			fmt.Println("receive close signal")
			return
		}
	}
}

老师，我想问一下上述代码会不会存在quitChan和taskChan同时收到消息，然后select执行了quitChan，此时给taskChan的任务是不是就丢失了？